Need math help fast

**bigDman** · 02-16-2006, 12:49 AM

okay i need help with my math

when you have something like inverse tan of 1 how do you find the answer without your calculator(i know its pie/4 but i dont know how to do it without my calculator) what if you have like inverse tan of 3/4

what about ig you have like sin of 30 degrees how do you do that without your calculator

or something like cos of 90 degrees?

**skelooth** · 02-16-2006, 01:12 AM

Why would you need or want to?

inverse tan of 3/4 is the value of tan when it's output is 3/4

so....

tan X= 3/4

Honestly I can't help, because I've always done this on the calculator. I don't know the functions for sin/cos/tan

**bigDman** · 02-16-2006, 01:14 AM

ugh

i figured it out

i need to because you need it in pre calc and were not aloud to use calculators in the class... so i have to memorize the unit circle(or atleast i think thats the easiest way)

**skelooth** · 02-16-2006, 01:15 AM

you're not allowed to use calculators in pre-calc class?!?!?!?!?!?!?!?!?? WHAT

I had my TI glued to my hand throughout the entire course

**bigDman** · 02-16-2006, 01:18 AM

nope
were not allowed to for 90% of the course

what is inverse tan60?

or what is .5/(radical3/2) as a fraction

this is what i figured out and i hope its right
cos30 is radical 3/2 and sin30 is 1/2 tan30 is radical3/4 cos45 and sin45 is radical2/2 and tan45 is 1 cos60 is 1/2 and sin60 is radical3/2 and tan60 is radical3/3 and then sin90 is 1 and cos90 is 0 and tan90 is 0

**skelooth** · 02-16-2006, 01:30 AM

.5/(radical3/2) is a fraction

inverse tan 60 is

tan X = 60

I don't know how to do that w/o a calculator, and I'm not sure how you could. Tan iirc is sin over cos? and the values for sin and cos range from -1 to 1.

Okay as long as you get to use your calc for 90 of the course... i see what your teacher is doing. He wants to make sure you understand how they work

sin and cos are easy if you just picture a 1 radian circle (The diameter is 2 radians and it's circumferance is 2 pi radians). each point on the circle can be represented by (cos(x), sin(x)). Later on in the course you start looking at them as waves...

aren't you glad i'm here to not be helpful? I tutor precalc, and if one of my students asked me to do what you're asking and I'd say "I have to use the bathroom" :zoom: then come back when the session was over.

**bigDman** · 02-16-2006, 01:32 AM

what is inverse tan60?

or what is .5/(radical3/2) as a fraction

you can find those out with your calc

i think its radical3/3 btu im not sure

**skelooth** · 02-16-2006, 01:33 AM

Quote:

sin90 is 1 and cos90 is 0 and tan90 is 0

Really important... you're working in DEGREES right? in radians that same statement would have been sin pi/2 is 1 and cos pi/2 is 0

**Trick D** · 02-16-2006, 01:37 AM

The memories of Trig... Man that was a long time ago. I don't remember how to do it.

**bigDman** · 02-16-2006, 01:38 AM

yea
degress
and tan90 is undifined not 0 right?

**skelooth** · 02-16-2006, 01:44 AM

actually trick, it only seems like trig

But after they cover right triangles in precalc you go directly to applying them to sin/cos waves.... which is just background information you need to know for amplitude and transitioning, then later on in actual calc it makes differentials and tangent lines make more sense

Tan 90 is undefined correct. Because at 90 degrees cos is 0. IE, Tan90= 1/0

**bigDman** · 02-16-2006, 01:51 AM

Quote:

Originally Posted by skelooth

actually trick, it only seems like trig

But after they cover right triangles in precalc you go directly to applying them to sin/cos waves.... which is just background information you need to know for amplitude and transitioning, then later on in actual calc it makes differentials and tangent lines make more sense

Tan 90 is undefined correct. Because at 90 degrees cos is 0. IE, Tan90= 1/0

thanks skel i think ill be ready for my test tommrow... the test is on polar graphs so i need to knoe all teh sin cos and tan junk

**skelooth** · 02-16-2006, 01:57 AM

no thank you. After that last post everything just clicked in my head and made sense

**Trick D** · 02-16-2006, 03:59 AM

I took calc 1 and business calculus... luckily we barely went into tangents... we stayed more into derivitives and antiderivitives.

**skelooth** · 02-16-2006, 03:00 PM

A derivitive is the slope of a tangent line

Tangent and tangent lines are different

HCClubPrez · 02-16-2006, 03:25 PM

LOL - I spent hours doing this stuff thru high school and college.

...and I don't remeber jack about it! :boink:

02-16-2006, 01:12 AM	#2
skelooth eh heh heh Join Date: Aug 2005 Location: Behind you Posts: 7,200 Recipes: 0 Rep Power: 158	Why would you need or want to? inverse tan of 3/4 is the value of tan when it's output is 3/4 so.... tan X= 3/4 Honestly I can't help, because I've always done this on the calculator. I don't know the functions for sin/cos/tan __________________ http://loseover100lbs.com/misc-f7.html

02-16-2006, 01:15 AM	#4
skelooth eh heh heh Join Date: Aug 2005 Location: Behind you Posts: 7,200 Recipes: 0 Rep Power: 158	you're not allowed to use calculators in pre-calc class?!?!?!?!?!?!?!?!?? WHAT I had my TI glued to my hand throughout the entire course __________________ http://loseover100lbs.com/misc-f7.html

02-16-2006, 01:30 AM	#6
skelooth eh heh heh Join Date: Aug 2005 Location: Behind you Posts: 7,200 Recipes: 0 Rep Power: 158	.5/(radical3/2) is a fraction inverse tan 60 is tan X = 60 I don't know how to do that w/o a calculator, and I'm not sure how you could. Tan iirc is sin over cos? and the values for sin and cos range from -1 to 1. Okay as long as you get to use your calc for 90 of the course... i see what your teacher is doing. He wants to make sure you understand how they work sin and cos are easy if you just picture a 1 radian circle (The diameter is 2 radians and it's circumferance is 2 pi radians). each point on the circle can be represented by (cos(x), sin(x)). Later on in the course you start looking at them as waves... aren't you glad i'm here to not be helpful? I tutor precalc, and if one of my students asked me to do what you're asking and I'd say "I have to use the bathroom" :zoom: then come back when the session was over. __________________ http://loseover100lbs.com/misc-f7.html

02-16-2006, 01:44 AM	#11
skelooth eh heh heh Join Date: Aug 2005 Location: Behind you Posts: 7,200 Recipes: 0 Rep Power: 158	actually trick, it only seems like trig But after they cover right triangles in precalc you go directly to applying them to sin/cos waves.... which is just background information you need to know for amplitude and transitioning, then later on in actual calc it makes differentials and tangent lines make more sense Tan 90 is undefined correct. Because at 90 degrees cos is 0. IE, Tan90= 1/0 __________________ http://loseover100lbs.com/misc-f7.html

02-16-2006, 01:57 AM	#13
skelooth eh heh heh Join Date: Aug 2005 Location: Behind you Posts: 7,200 Recipes: 0 Rep Power: 158	no thank you. After that last post everything just clicked in my head and made sense __________________ http://loseover100lbs.com/misc-f7.html

02-16-2006, 03:00 PM	#15
skelooth eh heh heh Join Date: Aug 2005 Location: Behind you Posts: 7,200 Recipes: 0 Rep Power: 158	A derivitive is the slope of a tangent line Tangent and tangent lines are different __________________ http://loseover100lbs.com/misc-f7.html

02-16-2006, 03:25 PM	#16
HCClubPrez Amateur Join Date: Feb 2006 Location: Wi. Posts: 36 Recipes: 0 Rep Power: 0	LOL - I spent hours doing this stuff thru high school and college. ...and I don't remeber jack about it! :boink:

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